The sum of 6 consecutive odd integers exceeds twice the biggest integer integer by 38. Find sum of the six numbers?

Question

Accepted Answer

72 (ব্যাখ্যা: let, 6 consecutive odd integer are: 2n - 5, 2n - 3, 2n - 1, 2n + 1, 2n + 3, 2n + 5. so, (2n - 5) + (2n - 3) + (2n - 1) + (2n + 1) + (2n + 3) + (2n + 5) = 2.(2n + 5) + 38 বা, 12n = 4n + 10 + 38 বা, 8n = 48 so, n = 6 sum of six numbers = 12 * 6 = 72)

Answer

42

Answer

50

Answer

60

The sum of 6 consecutive odd integers exceeds twice the biggest integer integer by 38. Find sum of the six numbers?

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